Find the value of the parameter a for which the root of the equation x^2 + 2(a-1)x +a + 5 = 0 are

a) opposite in sign

b) both roots are greater than 3

c) both roots are smaller than 3

d)one root is greater than 3 and other is smaller than 3

e) exactly one root lies between (1,3)

f) both roots lies between (1.3)

g) one root is smaller than 1 and other root is greater than 3 

Hi!
Here is the answer to your question.
 
The given quadratic equation is x2 + 2(a –1)x + (a + 5) = 0

Cheers!

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 answer question please, i am the paid user.thanks

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