Find the value of the parameter a for which the root of the equation x^2 + 2(a-1)x +a + 5 = 0 are
a) opposite in sign
b) both roots are greater than 3
c) both roots are smaller than 3
d)one root is greater than 3 and other is smaller than 3
e) exactly one root lies between (1,3)
f) both roots lies between (1.3)
g) one root is smaller than 1 and other root is greater than 3
Hi!
Here is the answer to your question.
The given quadratic equation is x2 + 2(a –1)x + (a + 5) = 0
Cheers!