Find the value of x:

2^2x+1 = 17.2^x - 2^3

Any one please solve this question

2^(2x+1) - (17)(2^x) + 8 = 0 2*2^(2x) - (17)(2^x) + 8 = 0 Let a = 2^x 2a² - 17a + 8 = 0 (2a - 1)(a - 8) = 0 2a - 1 = 0 2(2^x) - 1 = 0 2^(x + 1) - 1 = 0 2^(x + 1) = 1 2^(x + 1) = 2^0 x + 1 = 0 x = -1
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X=-1
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Hope this will help you

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X=1/2
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2^2x+1 = 17. 2^x - 2^3
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2^2x+1= 17.2^x-2^3
 
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2^(2×) -2^(×+2)+4=0

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This is like a joke with me and I am not satisfied with answer
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