find the value of X and Y..if 2X+3Y=[ 2 3 , 4 0 ] (2x2 matrix) and 3X+2Y=[ 2 -2 , -1 5 ] (2x2 matrix).

et 2x+3y=[ 2 3 , 4 0 ]-------(1)

 

3x+2y=[ 2 -1 , -1 5 ]------(2)

 

multiply the the equation (1) with 3.we get;

 

6x+9y=[ 6 9 , 12 0].-----(3)

 

then,multiply the equation (2) with 2.we get

 

6x+4y=[ 4 -4 , -2 10 ].----(4)

 

now subtract the equation (3) and (4)

 

(3)-(4).the we will get the answer as 5y=2 13 , 14 -10 ]

 

y=[ 2/5 13/5 , 14/5 -2 ]

 

now substitute the value of y in equation (1)

 

we get,2x+3[ 2/5 13/5 , 14/5 -2 ]=[ 2 3 , 4 0 ]

 

2x+[ 6/5 39/5 , 42/5 -6 ]=[ 2 3 , 4 0 ]

 

2x=[ 2 3 , 4 0 ]-[ 6/5 39/5 , 42/5 -6 ]

 

then 2x=[ 4/5 -24/5 , -22/5 6]

 

then x=[ 4/5 -24/5 , -22/5 6 ]/2

 

there fore x=[ 2/5 -12/5 , -11/5 3]

 

so x= 2/5 -12/5 , -11/5 3 ] and y=[ 2/5 13/5 , 14/5 -2 ]

 

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thank you madam...

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you are welcome 

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why to multiple 3 with equation one
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But why multiply with 3 and 2
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Find x and y if 2x +3y
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Open this pic

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Vinay

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Please give me a answer
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