find the value of x if (8/3)2x+1 * (8/3)5 = (8/3)x+ 2

832x+1 × 835 = 83x+2⇒832x+1+5 = 83x+2 as, am an = am+n⇒832x+6 = 83x+2⇒2x + 6 = x + 2⇒2x - x = 2 - 6⇒x = -4

find the value of x if (8/3)^2x+1* (8/3)⁵ = (8/3)^x+ ²

{(\frac{8}{3})}^{2 x + 1} \times {(\frac{8}{3})}^{5} = {(\frac{8}{3})}^{x + 2} \Rightarrow {(\frac{8}{3})}^{2 x + 1 + 5} = {(\frac{8}{3})}^{x + 2} [as, a^{m} . a^{n} = a^{m + n}] \Rightarrow {(\frac{8}{3})}^{2 x + 6} = {(\frac{8}{3})}^{x + 2} \Rightarrow 2 x + 6 = x + 2 \Rightarrow 2 x - x = 2 - 6 \Rightarrow x = - 4