Find the value of x in the following Share with your friends Share 0 Atul Shaw answered this Dear student, As AC=ABSo, ∠ACB=∠ABC=x∠ACB+∠ACD=180° (Linear Angle)⇒x+∠ACD=180°⇒∠ACD=180°-xAs AC=CDSo, ∠CAD=∠CDA=yin △ACD,∠ACD+∠CDA+∠DAC=180° (Sum of angles of a △)⇒180°-x+y+y=180°⇒2y=x⇒y=x2So, ∠CAD=x2in △ACB,∠ACB+∠ABC+∠CAB=180°⇒x+x+∠CAB=180°⇒∠CAB=180°-2xNow,∠DAC+∠CAB+96°=180° (Linear Angle)0.5x+180°-2x+96°=180°96°=1.5xx=64°Regards 2 View Full Answer