Find the value of x in the following

Dear student,

As AC=ABSo, ACB=ABC=xACB+ACD=180°   (Linear Angle)x+ACD=180°ACD=180°-xAs AC=CDSo, CAD=CDA=yin ACD,ACD+CDA+DAC=180° (Sum of angles of a )180°-x+y+y=180°2y=xy=x2So, CAD=x2in ACB,ACB+ABC+CAB=180°x+x+CAB=180°CAB=180°-2xNow,DAC+CAB+96°=180° (Linear Angle)0.5x+180°-2x+96°=180°96°=1.5xx=64°Regards

  • 2
What are you looking for?