find the value of 'x' so that lhs=rhs

3x+2(x+2)=20-(2x-5)

3x+2(x+2)=20-(2x-5)

3x+2x+4=20-2x+5

5x+4=25-2x

5x+2x=25-4

7x=21

x=21/7

x=3

  • 4

3x+2(x+2)=20-(2x-5)

3x+2x+4=20-2x+5

5x+4=25-2x

5x+2x=25-4

7x=21

x=21/7

x=3

  • 3

3x+2(x+2)=20-(2x-5)

3x+2x+4=20-2x+5

5x+4=25-2x

5x+2x=25-4

7x=21

x=21/7

x=3

  • 3

thanks

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