Find the values of Y for real x

Y= x2+2x-11
​ 2(x-3)

the given equation is :
y=x2+2x-112(x-3)2xy-6y=x2+2x-11x2+2x.(1-y)+6y-11=0for xR, D04.(1-y)2-4*(6y-11)0(1-y)2-6y+1101+y2-2y-6y+110y2-8y+120y2-6y-2y+120(y-6)(y-2)0y(-,2][6,)
hope this helps you

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