Find the velocity of projection and angle of projection of a missile which has horizontal range is 150m, if the time of flight for that range is 3 second (g=10m/s^2). Please answer it soon. Thank you Share with your friends Share 6 Satyendra Singh answered this R = u2 sin 2θg150 = u2 sin 2θ10 or,1500 = u2 sin 2θ1500 = u2 ×2 sinθ cosθ 750 = u2 sinθ cosθ ---- (1)and,T = u sinθg3 = u sinθ10 u sinθ = 30 ---- (2)substituting value of u sinθ from (2) in (1)750 = 30 u cosθu cos θ = 25 ----- (3)eq (2)eq (3) gives,tan θ = 3025 or,θ = 50.19onow,u = 25 cos 50.19 = 39.0476 ms -2 View Full Answer