Find the zeroes of p(x) = root 3x2+ 10x + 7 root 3 & the relation between the zeroes and coefficient of the polynomial.
√3x2 + 10x + 7√3 = 0
√3x2 + 7x + 3x + 7√3 = 0
x ( √3x + 7 ) + √3 ( √3x + 7 ) = 0
(x + √3) ( √3x + 7) = 0
x + √3 = 0 , √3x +7 = 0
x= -√3 x= -7/ √3
So, the 2 zeroes are -√3 and -7/√3
Sum of zeroes = -√3 + (-7/√3)
= -√3 - 7/√3
= -10/ √3 = -b/a
Product of zeroes = -√3 * - 7/√3
= 7 = c/a