Find the zeroes of p(x) = root 3x2+ 10x + 7 root 3 & the relation between the zeroes and coefficient of the polynomial.

 √3x2 + 10x + 7√3 = 0

√3x2 + 7x + 3x + 7√3 = 0

x ( √3x + 7 ) + √3 ( √3x + 7 ) =  0

(x + √3) ( √3x + 7) = 0

x + √3 = 0       ,        √3x +7 = 0

x= -√3                       x= -7/ √3

So, the 2 zeroes are -√3 and -7/√3

Sum of zeroes =  -√3 + (-7/√3)

                           = -√3 - 7/√3
                           = -10/ √3 = -b/a 
 
Product of zeroes = -√3 * - 7/√3
                                 = 7 = c/a
 

  • 120

 Hey!!!!!!!!!!!!!!!!!!!1jst  study ur self pathalllllllllle mole

  • -7

 in the place of X you can put any no. like 

1/2/3/4/5/6

etc

If the ans. is 0 then the coefficient is the no. which you have taken

  • 6

Thanks Anupriya {^ _ ^}

  • 5

find the quadratic polynomial whose sum is 1/2 and product is -7/6

  • -10
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