find the zeroes of the quadratic polynomial and verify the relationship between the zeroes and and coefficient of polynomial 6x2-x-2.

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The quadratic polynomial is f(x)= 6x2-x-2.


The zeros of f(x) are given by f(x) = 0

Either 2x+1=0  or  3x-2=0

x=-1/ 2  ,  x=2/3

 

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PART:1

 

6x2-x-2=0

x2 –x/6-2/6=0

x2-2x(1/12)+(1/12)2 = (1/12)2 +1/3

(x-1/12)2 =1/144 + 1/3

x-1/12=(3+144)/144*3

x-1/12=147/144*3  ={7*7*3/12*12*3}1/2

x=±7/12 + 1/12

x=8/12 or -6/12 = 2/3 or -1/2

 

PART:2

LET THE ROOTS BE α=2/3 AND β=-1/2

α+β=-b/a

2/3 + -1/2 = 1/6

(4-3)/6 = 1/6

1/6= 1/6

 

Αβ=c/a

(2/3)*(-1/2)=-2/6

-2/6=-2/6

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