find the zeros of polynomial f(x)=2x³- 9x²+x+12 can anybody answer asapplz Share with your friends Share 4 Ashutosh Verma answered this Answer : We have : 2x3 - 9x2 + x + 12 , And we can write : ⇒2x3 - 6x2 - 3x2 + 9x - 8x + 12 ⇒2x3 - 6x2 - 8x +- 3x2 + 9x+ 12 ⇒2x x2 - 3x - 4 - 3 x2 - 3x - 4 ⇒ 2x - 3 x2 - 3x - 4 ⇒ 2x - 3 x2 - 4x + x - 4 ⇒ 2x - 3 x x - 4 + 1 x - 4 ⇒ 2x - 3 x + 1 x - 4 Now, zeroes can be calculated by, 2x - 3 x + 1 x - 4 = 0⇒x = 32, -1, 4 -3 View Full Answer