Find two consecutive even positive integers, sum of whose squares is 290.

Since it is given that 290 is the sum of two consecutive positive even integers.

∴ Let the first even number be 2*x* and then the other even number will be 2*x* + 2.

According to the question,

∴ First even number= 2*x *= 2 × 5.5 = 11 and other even number = 2*x* + 2 = 11 + 2 =13

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