Find two consecutive multiples of 3 whose product is 648.

Let the required consecutive multiples of 3 be 3x and 3(x + 1).

According to the given condition,
3x×3x+1=6489x2+x=648x2+x=72x2+x-72=0
x2+9x-8x-72=0xx+9-8x+9=0x+9x-8=0x+9=0 or x-8=0
x=-9 or x=8
x = 8           (Neglecting the negative value)

When x = 8,
3x = 3 × 8 = 24
3(x + 1) = 3 × (8 + 1) = 3 × 9 = 27

Hence, the required multiples are 24 and 27.

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