Find value of x log3 (4 x) = log3 (x + 8) log2 (2x + 1) = - Maths - Permutations and Combinations

Question

Find value of x

log3 (4 − x) = log3
(x + 8)
log2 (2x + 1) = log2 (15)
log4 (x + 2) = log4 (55)
log5 (x + 1) = log5 (2x +
7)
log3 (x + 2) = log3 (3x
− 5)
log7 (x + 3) = log7 (5x
− 8)
log5 (−x + 1) = log5 (5 +
x)
log8 (2x + 4) = log8 (60)
log4 (x + 1) = log4 (10)
log4 (3x + 1) = log4 (2x)

Chandan chaurasiya · Accepted Answer

Dear student ï¿¼<img alt="" src=
"https://s3mn%20mnimgs%20com/img/shared/content_ck_images/ck_5d380cb027b06%20jpg">regards

Find value of x log3 (4 − x) = log3 (x + 8) log2 (2x + 1) = log2 (15) log4 (x + 2) = log4 (55) log5 (x + 1) = log5 (2x + 7) log3 (x + 2) = log3 (3x − 5) log7 (x + 3) = log7 (5x − 8) log5 (−x + 1) = log5 (5 + x) log8 (2x + 4) = log8 (60) log4 (x + 1) = log4 (10) log4 (3x + 1) = log4 (2x)