for A+B GIVES RISE TO C+D WHEN[A] ALONE IS DOUBLED ,RATE GETS DOUBLED BUT WHEN ALONE IS INCREASED BY 9 TIMES RATE GETS TRIPLED THEN ORDER OF REACTION IS

Ok. I am assuming you meant when 'B' alone is increased by 9 times...
If concentration of A is doubled and yet it still gives only double the reaction rate. This means stoichiometric co efficient of A should be 1 itself.

dR/dT = k[A]x[B]y   ...1
new eqn
2*dR/dT = k[2A]x[B]y  ....2
On solving 1 and 2, we get,
2 = 2x
x=1.

Now similarily for the second circumstance :
dR/dT = k[A]x[B]y   ...1

3*dR/dT = k[A]x[9B]y  ....2

On solving 1 and 2 we get,
3=9y
91/2 = 9y
y=1/2


So the order of the reaction would be 1 + 1/2 = 3/2 = 1.5

The order can be in fraction .
Hope this helped! :))
 
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