For a metallic wire, the ratio I (V= the applied bid., I= current flowing) is:
(a) Independent of temp.
(b) Increases as the temperature rises.
(C) Decreases as the temperature rises.
(d) Increases or decreases at temperature rises, depending upon the metal.
Solution
Assuming that you are asking about ratio V/I for metallic wire i am providing answer here. If there is anything else in your mind please reach again to us.
According to ohm's law
V =I R
So ration
V/I = R that is resistance of wire.
Resistance R is directly proportional to temperature.
It is becuase with the increase in temperature of conductor, both the random motion of electrons and the amplitude of vibration of fixed positive ions increase. As a result, the number of collisions increases. Hence, the resistance of a conductor increases with the increase in its temperature.
Thus ratio V/I increases as the temperature rises.
Assuming that you are asking about ratio V/I for metallic wire i am providing answer here. If there is anything else in your mind please reach again to us.
According to ohm's law
V =I R
So ration
V/I = R that is resistance of wire.
Resistance R is directly proportional to temperature.
It is becuase with the increase in temperature of conductor, both the random motion of electrons and the amplitude of vibration of fixed positive ions increase. As a result, the number of collisions increases. Hence, the resistance of a conductor increases with the increase in its temperature.
Thus ratio V/I increases as the temperature rises.