For a reaction, 2SO2(g)+O2(g)⇔2SO3(g) , 1 5 moles of SO2 and 1 mole of O2 are taken in a 2 - Chemistry -

Question

For a reaction, 2 S O 2 ( g ) + O 2 ( g ) ⇔ 2 S O 3 ( g ) , 1
5 moles of S O 2 and 1 mole of O 2 are taken in a 2 L vessel At
equilibrium the concentration of S O 3 was found to be 0 35 mol L -
1 The for the reaction would be

5 1 L m o l - 1
0 6 L m o l - 1
2 95 L m o l - 1
1 4 L m o l - 1

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Geetha · Accepted Answer

The given equilibrium is                            2SO2 + O2 ↔ 2 SO3Initial moles :    1
5           1            -At eqm          :    1
5-2x    1-x    2xno of moles                                                                Given that at equilibrium 2x = 0
35 mol/Lx= 0
175                        1
5-2(0 175)    1-0
175     2×0
175                      =1
15                  0
825             0
35Equilibrium concentration nv                             1
15 2             0
8252          0
352Kc = [SO3]2[SO2]2 [O2]       =  0
3522 1 15 2 20 8252   = 0
2245 L mol-1None of the option matches

For a reaction, 2 S O 2 ( g ) + O 2 ( g ) ⇔ 2 S O 3 ( g ) , 1.5 moles of S O 2 and 1 mole of O 2 are taken in a 2 L vessel. At equilibrium the concentration of S O 3 was found to be 0.35 mol L - 1 . The for the reaction would be 5.1 L m o l - 1 0.6 L m o l - 1 2.95 L m o l - 1 1.4 L m o l - 1 ​