# For charges q1 and q2, if force between them for some separation in air is F, then force between them in a medium of permitivity will be?

When a new medium is introduced between the charges q

_{1}and q

_{2}, then the electrostatic force will be ,

$F=\frac{1}{4\pi {\epsilon}_{0}{\epsilon}_{r}}\frac{{q}_{1}{q}_{2}}{{r}^{2}}\phantom{\rule{0ex}{0ex}}Here,permittivityofthemedium,\epsilon ={\epsilon}_{0}{\epsilon}_{r}\phantom{\rule{0ex}{0ex}}{\epsilon}_{r}=\frac{\epsilon}{{\epsilon}_{0}}$

Regards

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