For how many grams of CO2 gas, the product of pressure and volume will be equal to 40R lit-atm at 127??
Dear Student,
According to the question, PV = 40R L.atm
T = 127oC = (127 + 273) K = 400 K
Applying ideal gas equation, PV = nRT
40R = nR(400)
n = 0.1 moles
mass of CO2 = 0.1 mol 44 gmol-1 = 4.4 g
Regards
According to the question, PV = 40R L.atm
T = 127oC = (127 + 273) K = 400 K
Applying ideal gas equation, PV = nRT
40R = nR(400)
n = 0.1 moles
mass of CO2 = 0.1 mol 44 gmol-1 = 4.4 g
Regards