For the complex [Fe(C0)₅], write the hybridization, magnetic character and spin of the complex. (At. Number : Fe = 26 )

 
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Please find the solution to the asked query:

In the complex, [Fe(CO)₅] , Fe is present in the zero oxidation state
So its configuration is 3d⁶4s²
As  CO is a strong filed ligand, it forces pairing of the unpaired electrons, and thus the hybridisation of the Fe atom becomes dsp³

It is a diamagnetic complex as all electrons are paired.





Spin of the complex is :   Low spin. This is because the complex formed is an Inner orbital complex [ where the inner d orbitals are used in the hybridisation] which are Low spin in nature.
As there are no unpaired electrons n =0 and thus the magnetic moment of the complex  [$B.M =\sqrt{n(n+2) }B.M$] is 0
 

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