For the equilibrium SO3 (g) = SO2 (g) + 1/2 O2 (g), the molar mass at equilibrium was observed to be 60, then the degree of dissociation of SO3 would be? Answer is 0.66

2so3 2so2+o2

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This is the exact answer

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Give answer

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Which formula is thisplease tell me i have a doubt
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0.66
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SO3=SO2+1/2O2 n=1+(1/2)=3/2 Mt=molar mass of SO3=80 Degree of dissociation = Mt-Mo/(n-1)Mo =80-60/(3/2-1)×60=0.66=66%
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This is the answer

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2/3=0.666..

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