- For the reaction A +B --------- C + D doubling the concentration of both the reactants increases the reaction rate by 8 times and doubling the concentration of only B simply doubles the reaction rate. Find the rate law for the equation.
The rate of reaction becomes 2 times when the concentration of B is doubled, therefore rate with respect to B = 1
Now, rate of reaction becomes 8 times when concentration of both A and B is doubled.
Since, rate wr.r.t B is 1, it must be 2 w.r.t A
Hence, rate = k [A]2[B]
Putting A = 2 A and B = 2B, we can verify that rate = 8 times as follows:
Rate = k [2A]2[2B] = 8 x k [A]2[B]