For this question , for more that 13 defective parts u gave the answer 2/100=.02


Then how can we take it as 2 and total days as 100...total days are 200.right?

And in the question no such trial that more than 13 defective parts.

So the probability should be 0 right..?

For this question , for more that 13 defective parts u gave the answer 2/100=.02 Then how can we take it as 2 and total days as 100...total days are 200.right? And in the question no such trial that more than 13 defective parts. So the probability should be 0 right..? CBSE CLASS 10 STUDY ASK & ANSWER FEED I have seen the answer for atleast one defective part..but i didn't understand..can you 5. Over the past 200 working days, the number of defective parts produced by a is Determine the probability that tomorroW's outpĆ¼t will have (i) no defective part (ii) atleast one defective part (iii) not more than 5 defective parts (iv) more than 13 defective parts

Dear Student,

Please find below the solution to the asked query:

Yes you are absolutely right as total number of days  =  200 , So

And we Probability P ( E )  = Total number of desired events n ( E )Total number of events n ( S )

Here  ,

n ( S ) =200

And

To find probability of having more than 13 defective parts tomorrow we get , n ( E ) = 2  from the given data table , So 

Probability of having more than 13 defective parts tomorrow  = 2200 = 1100 = 0.01     ( Ans )
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