For what value of K, the quadratic equation kx (5x-6) + 9 =0 has equal roots?

Dear Student,
Here is the solution of your asked query:
kx5x-6+9=05kx2-6kx+9=0Comparing this with standard form of quadratic equation ax2+bx+c=0, we have;a=5k, b=-6k and c=9Since the given quadratic equation has equal roots so we have;D=b2-4ac=0-6k2-4×5k×9=036k2-180k=036kk-5=0kk-5=0k=0 or k=5Neglecting k=0 we have, k=5So the value of K should be 5.
Regards

  • 2
b^2-4ac=0
K=0
K=5
those are the values of K in given quadratic equation
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