for what value of k will 7/3 be a root of 3x2-13x-k=0.

Since 7/3 is a root of the equation, we can substitute 7/3 in the equation

3(7/3)^2 - 13(7/3)-k=0

3(49/9) -13*7/3= k

49/3- 91/3=k

-42/3=k

-14=k

Hence, k= (-14)

  • 10
What are you looking for?