for what value of k will 7/3 be a root of 3x2-13x-k=0.
Since 7/3 is a root of the equation, we can substitute 7/3 in the equation
3(7/3)^2 - 13(7/3)-k=0
3(49/9) -13*7/3= k
49/3- 91/3=k
-42/3=k
-14=k
Hence, k= (-14)
for what value of k will 7/3 be a root of 3x2-13x-k=0.
Since 7/3 is a root of the equation, we can substitute 7/3 in the equation
3(7/3)^2 - 13(7/3)-k=0
3(49/9) -13*7/3= k
49/3- 91/3=k
-42/3=k
-14=k
Hence, k= (-14)