for what value of K will the following pair of linear equation have no solution
3x+y=1
(2k-1)x+(k-1)y=2k+1
Given system of equations is:
3x+y=1 and
(2k-1)x+(k-1)y=2k+1
They can be rewrite as:
3x + y - 1 = 0 and
(2k-1)x + (k-1)y - (2k+1) = 0
We know that, for the given system to have no solution, 
= 
≠ 
⇒ 
⇒ 3k - 3 = 2k - 1
⇒ k = 3-1
⇒ k = 2
Hence, for k = 2, the given system of equation will have no solution.