for what values of x and y are the nos. 3+ix^2y and x^2 + y+ 4i conjugate complexes? plz help..!!

meritnation, plz reply to the students. They need ur help..!!

 hey Rheeya just solve this u'll get the ans...
3+ix²y = (x²+y) - (4i)

on compairing real numbers nd complex number u'll get 
3 = x²+y ------- (i)     and     x²y = -4 ---------------(ii)
nd then putting x² = 3-y    in equation (ii)  [from i ]
(3 - y) (y) = -4
3y - y² = -4 
y² -3y -4 = 0
on solving this u'll get d answer .... :)
 

nd tell me if we have to find the real values of x nd y or not..... 

 thx :)