meritnation, plz reply to the students. They need ur help..!!

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Anubhav Gangwar answered this

hey Rheeya just solve this u'll get the ans... 3+ix^{2}y = (x^{2}+y) - (4i)

on compairing real numbers nd complex number u'll get 3 = x^{2}+y ------- (i) and x^{2}y = -4 ---------------(ii) nd then putting x^{2} = 3-y in equation (ii) [from i ] (3 - y) (y) = -4 3y - y^{2} = -4 y^{2} -3y -4 = 0 on solving this u'll get d answer .... :)

0

Anubhav Gangwar answered this

nd tell me if we have to find the real values of x nd y or not.....

-17

Rheeya answered this

thx :)

-2

Aastik Yadav answered this

Answer mine also

5

Srishti Mittal answered this

The value of x is +2 and -2 and the value of y is -1 and 4..