calculate the force b/w 2 alpha particles seperated by a distance of 3.2 x 10 ^-11 m .

According to Coulomb’s law of electrostatic force:

F= Kq₁q₂/r²

Here q₁ = q₂ = 2 x(1.6 x 10^-19)C

=3.2 x 10^-19C

r= 3.2 x 10 ^-11 m 

Therefore,

$$\begin{gathered} F = \frac{9\times {10}^{9 }\times (3.2\times {10}^{-19}{)}^2}{(3.2\times {10}^{-11}{)}^2} \\ = \frac{9\times {10}^9\times 10.24\times {10}^{-38}}{10.24\times {10}^{-22}} \\ = 9\times {10}^{-7 }N \end{gathered}$$