Force forming a couple are of magnitude 12N each and the arm of the couple is 8m. The force of an equivalent couple whose arm is 6m is of magnitude.

Dear Student,Here, F=12 Nr=8 mMagnitude of Torque produced, τ=FrOr, τ=12×8=96 Nm Now , when the arm length is changedr'=6 mAs magnitude o Torque produced is same So, F'r' =96Or, F'×6=96Or, F' =966Therefore, F'=16 NRegards

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