Force forming a couple are of magnitude 12N each and the arm of the couple is 8m. The force of an equivalent couple whose arm is 6m is of magnitude. Share with your friends Share 0 Sagar Kumar answered this Dear Student,Here, F=12 Nr=8 mMagnitude of Torque produced, τ=FrOr, τ=12×8=96 Nm Now , when the arm length is changedr'=6 mAs magnitude o Torque produced is same So, F'r' =96Or, F'×6=96Or, F' =966Therefore, F'=16 NRegards 0 View Full Answer