Force of 16N and 12N are acting on a mass of 200kg in mutually perpendicular directions Find the magnitude of - Physics - Laws Of Motion

Question

Force of 16N and 12N are acting on a mass of 200kg in mutually
perpendicular directions Find the magnitude of acceleration
produced?

Nitin Kakwani · Accepted Answer

Force 1 = a = 12 N , Force 2 = b =16 N m=200 kg $F= sqrt{a^{2}+b^{2}+2 a b costheta }$ $F= sqrt{a^{2}+b^{2}$ $F= sqrt{16^{2}+12^{2}$ $F=20 N$ $a= frac{F}{m} = frac{20}{200} = 0 1m/s^{2}$

Force of 16N and 12N are acting on a mass of 200kg in mutually perpendicular directions.Find the magnitude of acceleration produced?