form a quadratic polinomial whose one zero is 8 and the product of the zeroes is -56

Let a and b be the zeros of the said quadratic polynomial.

Given, a = 8 

Now, product of zeros = a × b = -56

⇒ 8 × b = -56

⇒ b = -7

Now, sum of zeros = a + b = 8 + (-7) = 1

So, the required polynomial = k(x² - (sum of zeros)x + (product of zeros)) where k is a constant

= k(x² - 1x -56)