Formation of polyethylene from calcium carbide takes place as follows: - Chemistry - Basic Concepts in Chemistry

Question

Formation of polyethylene from calcium carbide takes place as
follows:
CaC2 + H2O ->
Ca(OH)2 + C2H2 ->
C2H4
​ ​n(C2H4) -> (
-CH2-CH2- )n
Determine the amount of polyethylene possibly obtainable from 64 0
kg CaCl2

Shruti Srivastava · Accepted Answer

Dear â€‹Nevadhya,

In question the amount 64 kg of CaC2  instead of CaCl2 
The short form of reaction is:CaC2 →C2H464 g CaC2=28 g C2H4and 28 g C2H4 will for 28 g polythene (no wt loss when ethene forms polyethene)So accordingly 64 kg of CaC2=28 kg of C2H4and 28 kg of C2H4 will form 28 kg of polythene

Regards

Formation of polyethylene from calcium carbide takes place as follows: CaC2 + H2O -> Ca(OH)2 + C2H2 -> C2H4 ​ ​n(C2H4) -> ( -CH2-CH2- )n Determine the amount of polyethylene possibly obtainable from 64.0 kg CaCl2 .

Formation of polyethylene from calcium carbide takes place as follows:
CaC₂ + H₂O -> Ca(OH)₂ + C₂H₂ -> C₂H₄
n(C₂H₄) -> ( -CH₂-CH₂- )_n
Determine the amount of polyethylene possibly obtainable from 64.0 kg CaCl₂ .