Formation of polyethylene from calcium carbide takes place as follows:
           CaC2 + H2O -> Ca(OH)2 + C2H2 -> C2H4
          ​  ​n(C2H4) -> ( -CH2-CH2- )n
Determine the amount of polyethylene possibly obtainable from 64.0 kg CaCl2 .
 

Dear ​Nevadhya,

In question the amount 64 kg of CaC2  instead of CaCl2 .The short form of reaction is:CaC2 C2H464 g CaC2=28 g C2H4and 28 g C2H4 will for 28 g polythene (no wt loss when ethene forms polyethene)So accordingly 64 kg of CaC2=28 kg of C2H4and 28 kg of C2H4 will form 28 kg of polythene.

Regards

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Please find this answer

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 Carbon is 24/64 of CaC2. Ca (40) + C2 (24) = 64 
So carbon is 24/64 of the 64 kg = 24 kg. 
Carbon is 12/14 of polyethylene, formula (CH2)n = C (12) + H2 (2) = 14 (all times n). 

So if you have 24 kg of carbon, that will make 24 x 14/12 = 28 kg of polyethylene. 

D. Final answer.
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