Four faradays of electricity were passwd thru AgNO3, CdSO4.AlCl3 and PbCl4 kept in four vessels using inert electrodes.The ratio of moles of Ag,Cd, Al and Pb deposited will be. Share with your friends Share 32 Vartika Jain answered this Dear Student, Ag+(aq) + e- → Ag(s) 1 mol = 1F 1 mol 3F 3 molCd2+(aq) + 2e- → Cd(s) 2 mol = 2F 1 mol 3F 32 molAl3+(aq) + 3e- → Al(s) 3 mol = 3F 1 molPb4+(aq) + 4e- → Pb(s) 4 mol = 4F 1 mol 3F 34 mol Therefore, ratio = 3:32:1:34= 12:6:4:3 78 View Full Answer Dishank Gupta answered this Any doubt can ping me at the whatspp 7509598949 -22