From a top of a 7m high building, the angle of elevation of the top of a cable tower is 60 degree & the angle of depression of its foot is 45 degree. Determine the height of the tower.

PLZ ANSWER IN UNDERROOTS & WITH THE FIGURE.

Let AB be the building and CD be the tower such that <EAD = 60^{o} and <EAC = <ACB = 45^{o}

Now, In triangle ABC, tan 45 = 1 = AB/BC

So, AB = AE = 7 m

Again in triangle AED,

tan 60 = root 3 = DE/AE

So, DE= AE.root3 = 7 . root3 m

Height of the cable tower = h + 7 = 7 root 3 m+ 7 m =** 7 (1+ root3) m**

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