From a top of a 7m high building, the angle of elevation of the top of a cable tower is 60 degree & the angle of depression of its foot is 45 degree. Determine the height of the tower.
PLZ ANSWER IN UNDERROOTS & WITH THE FIGURE.
Let AB be the building and CD be the tower such that <EAD = 60o and <EAC = <ACB = 45o
Now, In triangle ABC, tan 45 = 1 = AB/BC
So, AB = AE = 7 m
Again in triangle AED,
tan 60 = root 3 = DE/AE
So, DE= AE.root3 = 7 . root3 m
Height of the cable tower = h + 7 = 7 root 3 m+ 7 m = 7 (1+ root3) m