From the following data find median age of 100 residents of a colony who took part in swachch bharat abhiyan:
Age(more than or equal to):0,10,20,30,40,50
No. of residents:50,46,40,20,10,3
PLZZ DO NOT GIVE LINKS......

Dear student,

According to the given observation,
 
Class Interval (CI) Frequency (f) Cumulative frequency Midpoint of CI (x) fx
0-10 50 50 5 250
10-20 46 96 15 690
20-30 40 136 25 1000
30-40 20 156 35 700
40-50 10 166 45 450
50-60 3 169 55 165
  N=f=169     fx=3255


mean=fxN=3255169=19.26To find median we apply the formulaMedian=L+N2-Ff×iwhere, i=size of class intervalL=lower limit of the CI which includes the median score.F=Cumulative frequency upto median CIf=frequency in the class interval that contains the medianN2=1692=84.5 ; L=20 ; F=15 ; i=10; f=40Thus, the median=20+84.5-1540×10=20+69.540×10=20+17.375=37.375
Regards

  • -1
according to given observation: class interval (CI) frequency f cumulative frequency midpoint of CI (x) fx 0-10 5 5 5 25 10-20 8 13 15 120 20-30 15 28 25 375 30-40 20 48 35 700 40-50 14 62 45 630 50-60 8 70 55 440 60-70 5 75 65 325 75 2615 mean = to find the median : we will apply the formula ; median = 75/ 2 = 37.5. this lies in the interval 30-40. i = size of the class interval L = lower limit of the CI which includes the median score. F = cumulative frequency up to median CI f = frequency in the class interval that contains the median. therefore L = 30 ; F = 28 ; f = 20 ; i =10 thus median =
  • 4
Thus median=

  • 0
I'm sorry....i didn't undrstand
  • -1
What are you looking for?