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**From the following distribution of monthly income of 60 people in a company. Draw less than and more than ogive curve and find the median on the graph.Find the median using the formula. Please can I get the answer quickly.**

Monthly income in thousand number of people

10-20 6

20-30 9

30-40 10

40-50 15

50-60 12

60-70 8

I tried this but I am getting median in graph differently than the value I am calculating using the formula.

Monthly income in thousand number of people

10-20 6

20-30 9

30-40 10

40-50 15

50-60 12

60-70 8

I tried this but I am getting median in graph differently than the value I am calculating using the formula.

Item( X) |
Frequency( f) |
Cumulative Frequency(c. f) |

10$-$20 | 6 | 6 |

20$-$30 | 9 | 15 |

30$-$40 | 10 | 25 |

40$-$50 | 15 | 40 |

50$-$60 | 12 | 52 |

60$-$70 | 8 | 60 |

$\sum f=N=60$ |

Median class is given by the size of the ${\left(\frac{N}{2}\right)}^{\mathrm{th}}$ item, i.e. the ${\left(\frac{60}{2}\right)}^{\mathrm{th}}$ item, which is the 30

^{th}item.

This corresponds to the class interval 40$-$50, so this is the median class.

$\mathrm{Median}\left(M\right)={l}_{1}+\frac{{\displaystyle \frac{N}{2}-c.f}}{f}\times i\phantom{\rule{0ex}{0ex}}\Rightarrow \mathrm{Median}\left(M\right)=40+\frac{{\displaystyle \frac{60}{2}-25}}{15}\times 10\phantom{\rule{0ex}{0ex}}\Rightarrow \mathrm{Median}\left(M\right)=40+\frac{{\displaystyle 50}}{15}\phantom{\rule{0ex}{0ex}}\Rightarrow \mathrm{Median}\left(M\right)=43.33\phantom{\rule{0ex}{0ex}}$

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