From the following reaction sequence
.Cl2 + 2KOH ------> KCL+KCLO+H2O
.3KCLO ------> 2KCL+ KCLO3
.4KCLO3 ------> 3KCLO 4 + KCL
Calculate the mass of chlorine needed to produce 100g of KCLO4
Dear student!
Here, we can see that, 3 moles of KClO4 produced by = 4 moles of KClO3
So, 1 mole of KClO4 is produced by = 4/3 = 1.33 moles of KClO3
Now, again we look for formation of KClO3 , we see that,
1 mole of KClO3 is produced by = 3 moles of KClO = 3 moles of Cl2 (as 1 mole Cl2 gives = 1 mole KClO)
so, 1.33 moles of KClO3 will require = 3 x 1.33 moles of Cl2 = 3.99 moles of Cl2
Hence, 4 moles of KClO4 requires = 3.99 moles of Cl2
So 1 mole= 138.5 gm of KClO4 requires = 3.99 moles of Cl2 = 283.29 gm of Cl2
Hence, 100 gm KClO4 will be produced by = 283.29/138.5 x 100 = 204.5 gm of Cl2