from the top of the fire tower , a forest ranger sees his partner on the ground at an angle of depression of 40 degree. if the tower is 45 feet in height how far is the partner from the base of the tower,to the nearest tenth of a foot?

Conisder the following figure which shows a fire tower AB and the position of fire ranger's partner at point C.

In right angle traingle ABC, we have    ABBC=tanCSubstitute the values to get,     45BC=tan40°    BC= 45tan40°The approximate value of tan 40° is 0.8391So it implies that,  BC= 450.8391        =53.63        54Thus the man's partner is at a distance of 54 feet from the base of the tower


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