Gauss's law is based on the inverse square independence on distance contained in the coulomb's law. Any violation of Gauss's law will indicate departure from the inverse square law. Explain the statement.
Dear Student.
Gauss's law is based on the inverse square dependence* on distance contained in the coulomb's law. Any violation of Gauss's law will indicate departure from the inverse square law:
Explanation,
Gauss's law is based on the inverse square law. Lets say if the instead of 1/r2 it is 1/r3. This will violate the Gauss's law.
Its simply showing that Gauss's law depends on inverse square law.
Or say if any we have any system that violates Gauss's law it will also violate the inverse square law.
Hope this helps you clear your doubt.
Regards.
Gauss's law is based on the inverse square dependence* on distance contained in the coulomb's law. Any violation of Gauss's law will indicate departure from the inverse square law:
Explanation,
Gauss's law is based on the inverse square law. Lets say if the instead of 1/r2 it is 1/r3. This will violate the Gauss's law.
Its simply showing that Gauss's law depends on inverse square law.
Or say if any we have any system that violates Gauss's law it will also violate the inverse square law.
Hope this helps you clear your doubt.
Regards.
