genomic dna is digested with Alu 1, a restriction enzyme which is a four base pair cutter. what is the frequency with which it will cut the dna assuming a random distribution of bases in the genome?
a. 1/4 b.1/24 c. 1/256 d.1/1296
Dear Student.
Please find below the solution to the asked query.
The answer is c. 1/256.
The formula is 4n, where n = number of base pair cut by enzyme.
So frequency will be. 1/4n.
For Alu1, which is a four base cutter, so the frequency will be 1/44.
The answer is 1/256.
Same way, if the enzyme is ECORI, which is a six base cutter, the frequency will be. 1/46. The frequency will be 1/4096.
Hope this information will clear your doubts about the topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards.
Please find below the solution to the asked query.
The answer is c. 1/256.
The formula is 4n, where n = number of base pair cut by enzyme.
So frequency will be. 1/4n.
For Alu1, which is a four base cutter, so the frequency will be 1/44.
The answer is 1/256.
Same way, if the enzyme is ECORI, which is a six base cutter, the frequency will be. 1/46. The frequency will be 1/4096.
Hope this information will clear your doubts about the topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards.