Give answers to all bellow given question.

Dear student,
Q9
Distance travelled = area under the curve
$\frac{Dis\tan ce travelled in the last two sec}{total dis\tan ce covered}=\frac{Area of triangle BCD}{Area of Trapezium OABC}=\frac{1/2\times 2\times 20}{1/2\times 20\times (7+2)}=\frac{2}{9}$

Option b is correct
Post other questions in a different thread with a better image
Regards