give solution please fast step by step
Dear student ,
Since , conductivity (k) = Conductance x cell constant or (C.C.)
Now since the conductivity cell is same then its cell constant is also same in both the experiments ,
Now for 0.1 M KCl solution ,1.29 = ( 1/100 ) x cell constant
cell constant = 129 cm
Again for 0.02 M KCl solution , k = ( 1/ 520) x 129 = 0.248 siemen cm-1
now again we know that , molar condutance = 1000 k / M
So for 0.02 M KCl , molar conductance = 1000 x 0.248 / 0.02 = 1.2 x 104 siemen mol-1
Regards
Since , conductivity (k) = Conductance x cell constant or (C.C.)
Now since the conductivity cell is same then its cell constant is also same in both the experiments ,
Now for 0.1 M KCl solution ,1.29 = ( 1/100 ) x cell constant
cell constant = 129 cm
Again for 0.02 M KCl solution , k = ( 1/ 520) x 129 = 0.248 siemen cm-1
now again we know that , molar condutance = 1000 k / M
So for 0.02 M KCl , molar conductance = 1000 x 0.248 / 0.02 = 1.2 x 104 siemen mol-1
Regards