Give the electronic configuration of d-orbitals of K3 [Fe(Cn)6] and K3[FeF6] and explain why these complexes give different colour with same solution.

In both K3[Fe(CN)6] and K3[FeF6], iron is in +3 oxidation state, that is the number of d-electrons in Fe3+ ion is 5. However, the ligand field strength in both these complexes would be different since the cyanide ion (CN- ion) is a strong ligand while the F- ion is a weak ligand. Hence, CN- would cause the pairing of electrons because of which the electronic arrangement in Fe in K3[Fe(CN)6] will be (t2g5)(eg). 

On the other hand, the F- ion being a weak ligand will not cause the pairing of electrons, because of which the electronic arrangement of Fe in K3[FeF6] will be (t2g3)(eg2). 

In both these complexes, iron possesses different number of unpaired electrons. Hence both these complexes will show different d-d transitions and therefore exhibit different colours in same solution. 

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