Give the structure of an optically active hydrocarbon(C6H12) which on catalytic hydrogenation gives an optically inactive compound (C6H14).

1. The optically active C₆H₁₂ hydrocarbon is 3-Methylpent-1-ene,having one chiral carbon as shown :

      

2. On Catalytic hydrogenation,the compound obtained is :

Above molecule has no chiral carbon.

3. The reaction is as follows :

   C₆H₁₂$\underset{Pd}{\overset{H_2}{\to }}$ C₆H₁₄