given a square matrix A of order 3x3 such that |A| =12 then find the value of |A adjA|

A adjA can be easily found by the following formula

A.adjA = adjA.A = |A|I


Therefore |A.adjA|can be find easily as,

|A.adjA|=||A|*I | 

|A.adjA|=|A|3.| I |

|A.adjA|=123.1=1728
using the determinant property that |cA|=(c^n)*|A| and n here is 3 and A=I
  • 9
Refer to this answer

  • 10
A square matrix of order 3 into 3 and A deteminant is 12 find | A adjoint A |
  • 3
Jjji
  • -3
What are you looking for?