Given that the equilibrium constant for the reaction
2SO2 + O2 ------> 2SO3
has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the reaction at the same temperature
SO3 -----> SO2+ ½O2
2SO2 + O2 <=> 2SO3 ---------Kc=278
SO3 <=> SO 2 + 1/2O2 ----------Kc'=(1/Kc)1/2
Kc'=(1/278)1/2 = 0.0599 = 5.9 x 10-2 =6x10-2
SO3 <=> SO 2 + 1/2O2 ----------Kc'=(1/Kc)1/2
Kc'=(1/278)1/2 = 0.0599 = 5.9 x 10-2 =6x10-2
