Given that the standard electrode potentials (E degrees) of metals are: K*/K=-2 93 V ,Ag*/Ag=0 80 V ,Cu^ 2+ /Cu=0 - Chemistry - Electrochemistry

Question

Given that the standard electrode potentials (E degrees) of metals
are: K*/K=-2 93 V ,Ag*/Ag=0 80 V ,Cu^ 2+ /Cu=0 34 V ,Mg^ 2+ /Mg=-2
37 V ,Cr^ 3+ /Cr=-0 74 V ,Fe^ 2+ /Fe=-0 44 V Arrange these metals
in increasing order of their reducing power

Ajay Soni · Accepted Answer

Solution -

Metal with most positive standard electrode potential has the least
reducing power
And, Metal with most negative standard electrode potential has
maximum reducing power
so, the order will be
Ag2+/Ag < Cu2+/Cu <
Fe2+/Fe < Cr3+/Cr < Mg2+/Mg
< K+/K

Given that the standard electrode potentials (E degrees) of metals are: K*/K=-2.93 V ,Ag*/Ag=0.80 V ,Cu^ 2+ /Cu=0.34 V ,Mg^ 2+ /Mg=-2.37 V ,Cr^ 3+ /Cr=-0.74 V ,Fe^ 2+ /Fe=-0.44 V. Arrange these metals in increasing order of their reducing power.

Given that the standard electrode potentials (E degrees) of metals are: K/K=-2.93 V ,Ag/Ag=0.80 V ,Cu^ 2+ /Cu=0.34 V ,Mg^ 2+ /Mg=-2.37 V ,Cr^ 3+ /Cr=-0.74 V ,Fe^ 2+ /Fe=-0.44 V. Arrange these metals in increasing order of their reducing power.