gravitational field in a region is given by E=(3i-4j) N/kg.Find out the work done in moving a mass of 1kg by 1m along the line 4y=3x+9
 

E=3i-4j  N/kgslope of the line m=34tanθ=34sinθ=35,cosθ=45unit vector in the direction of the line.r^=45i^+35j^find the angle between the E and rcosα=E.rE=05=0hence the angle between the field and the displacement is 90 degree.hence the work done in moving mass along the line is zero as this line is perpendicular to the field.Regards

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