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H3PO3 basicity is 2 even though the acid has 3 H's. why?

No, no that isn't the way you calculate the basicity of an acid!! Basicity is defined as the no. of ionizable or replacable hydrogen atoms in an acid on reaction with a base. It is NOT necessarily the no. of hydrogen atoms in the molecular formula of the acid. The basicity is determined by the number of H atoms attached directly to the O atom in the molecule. In order to find the no. of replacable hydrogen atoms in H3PO3, we must thus know its stucture:

Here since 2 H atoms are directly linked to O thus forming 2 -OH groups, therefore the basicity of H3PO3 is 2.

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only 2 acidic H+ are present.  

                    O

                     ||

              H-P-OH

                     |

                    OH

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  This the structure

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The basicity of an acid is determined by the number of hydrogen atoms linked directly to oxygen atom in the molecule.

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basicity is due to two oh bonds
.. not h
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the basicity of molecule depend upon removal of hydrogen that's why due to two ( Oh) bond removal of 2 hydrogen get easily that's why it's basicity is 2
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While Counting basicity of any molecule we cout number of OH not H
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Basicity is the no. of hydrogen atom ATTACHED to the oxygen atom.So in H3PO3 structure there are 3 H atoms but among them only two are attached to the hydrogen molecule
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Basicity is no. Of OH bonds in a given molecule ..we can find d basicity based on structure.H3PO3has 2 OH groups so its basicity is 2
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