haemoglobin contains 0.25% iron by weight. The molecular weight of haemoglobin is 896000. Calculate the number o iron atom per molecule of haemoglobin.

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Mass % of Fe in Hb = Mass of one Fe/ Mass of Hb(given) X 100

therefore

, 0.25 = x/89600 X 100

x = 224g.

this is the mass of Fe present in the amount of haemoglobin given to us. Now to find the number of Fe atoms simple divide the mass of obtained Fe by the standard mass of fe which is 56.

therefore, 224/56 = 4 atoms!

there you go !!

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0.25=x​​/89600 ×100




X=224g



224/56= 4atoms
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Mass % of Fe in Hb = Mass of one Fe/ Mass of Hb(given) X 100

therefore

, 0.25 = x/89600 X 100

x = 224g.

this is the mass of Fe present in the amount of haemoglobin given to us. Now to find the number of Fe atoms simple divide the mass of obtained Fe by the standard mass of fe which is 56.

therefore, 224/56 = 4 atoms!

there you go !!
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Molecular mass of haemoglobin = 89600 0.25% of iron present in haemoglobin have = 89600×0.25/100 = 224 1% of molecule contain 89600×1/100= 896. No. Of iron atoms per molecule = value of 1% molecule/value of iron present in haemoglobin No of iron atoms = 896/224= 4
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Answer

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In haemoglobin fe wait is .25*89600/100 =224gm
We know
In 56gm fe contains 1atom
So in 224gm= 1*224gm/56 =4atom
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